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Solve for x, y
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3x=-5
Consider the first equation. Subtract 5 from both sides. Anything subtracted from zero gives its negation.
x=-\frac{5}{3}
Divide both sides by 3.
5y-\frac{5}{3}=10
Consider the second equation. Insert the known values of variables into the equation.
5y=10+\frac{5}{3}
Add \frac{5}{3} to both sides.
5y=\frac{35}{3}
Add 10 and \frac{5}{3} to get \frac{35}{3}.
y=\frac{\frac{35}{3}}{5}
Divide both sides by 5.
y=\frac{35}{3\times 5}
Express \frac{\frac{35}{3}}{5} as a single fraction.
y=\frac{35}{15}
Multiply 3 and 5 to get 15.
y=\frac{7}{3}
Reduce the fraction \frac{35}{15} to lowest terms by extracting and canceling out 5.
x=-\frac{5}{3} y=\frac{7}{3}
The system is now solved.