\left\{ \begin{array} { l } { 3 x + 5 = 0 } \\ { 3 y - 10 = 0 } \end{array} \right.
Solve for x, y
x = -\frac{5}{3} = -1\frac{2}{3} \approx -1.666666667
y = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333
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3x=-5
Consider the first equation. Subtract 5 from both sides. Anything subtracted from zero gives its negation.
x=-\frac{5}{3}
Divide both sides by 3.
3y=10
Consider the second equation. Add 10 to both sides. Anything plus zero gives itself.
y=\frac{10}{3}
Divide both sides by 3.
x=-\frac{5}{3} y=\frac{10}{3}
The system is now solved.
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Limits
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