Solve {l}{3x+4=0}{x-y=1}

$$\left\{ \begin{array} { l } { 3 x + 4 = 0 } \\ { x - y = 1 } \end{array} \right.$$

Solve for x, y

$$x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$$

$$y = -\frac{7}{3} = -2\frac{1}{3} \approx -2.333333333$$

Solution Steps

Consider the first equation. Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$3x=-4$$

Divide both sides by 3.

$$x=-\frac{4}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$-\frac{4}{3}-y=1$$

Add \frac{4}{3} to both sides.

$$-y=1+\frac{4}{3}$$

Add 1 and \frac{4}{3} to get \frac{7}{3}.

$$-y=\frac{7}{3}$$

Divide both sides by -1.

$$y=\frac{\frac{7}{3}}{-1}$$

Express \frac{\frac{7}{3}}{-1} as a single fraction.

$$y=\frac{7}{3\left(-1\right)}$$

Multiply 3 and -1 to get -3.

$$y=\frac{7}{-3}$$

Fraction \frac{7}{-3} can be rewritten as -\frac{7}{3} by extracting the negative sign.

$$y=-\frac{7}{3}$$

The system is now solved.

$$x=-\frac{4}{3} y=-\frac{7}{3}$$