\left\{ \begin{array} { l } { 3 x + 2 y - 6 = 0 } \end{array} \right.
Solve for x
x=-\frac{2y}{3}+2
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3x-6=-2y
Subtract 2y from both sides. Anything subtracted from zero gives its negation.
3x=-2y+6
Add 6 to both sides.
3x=6-2y
The equation is in standard form.
\frac{3x}{3}=\frac{6-2y}{3}
Divide both sides by 3.
x=\frac{6-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+2
Divide -2y+6 by 3.
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