\left\{ \begin{array} { l } { 3 x + 2 y = 7 } \\ { x = 5 } \end{array} \right.
Solve for x, y
x=5
y=-4
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3\times 5+2y=7
Consider the first equation. Insert the known values of variables into the equation.
15+2y=7
Multiply 3 and 5 to get 15.
2y=7-15
Subtract 15 from both sides.
2y=-8
Subtract 15 from 7 to get -8.
y=\frac{-8}{2}
Divide both sides by 2.
y=-4
Divide -8 by 2 to get -4.
x=5 y=-4
The system is now solved.
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