Solve {l}{3x+2y=15}{3y+4=16}

$$\left\{ \begin{array} { l } { 3 x + 2 y = 15 } \\ { 3 y + 4 = 16 } \end{array} \right.$$

Solve for x, y

$$x = \frac{7}{3} = 2\frac{1}{3} \approx 2.333333333$$

$$y=4$$

Solution Steps

Consider the second equation. Subtract 4 from both sides.

$$3y=16-4$$

Subtract 4 from 16 to get 12.

$$3y=12$$

Divide both sides by 3.

$$y=\frac{12}{3}$$

Divide 12 by 3 to get 4.

$$y=4$$

Consider the first equation. Insert the known values of variables into the equation.

$$3x+2\times 4=15$$

Multiply 2 and 4 to get 8.

$$3x+8=15$$

Subtract 8 from both sides.

$$3x=15-8$$

Subtract 8 from 15 to get 7.

$$3x=7$$

Divide both sides by 3.

$$x=\frac{7}{3}$$

The system is now solved.

$$x=\frac{7}{3} y=4$$