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5x+5=3\left(x+5\right)
Consider the second equation. Use the distributive property to multiply 5 by x+1.
5x+5=3x+15
Use the distributive property to multiply 3 by x+5.
5x+5-3x=15
Subtract 3x from both sides.
2x+5=15
Combine 5x and -3x to get 2x.
2x=15-5
Subtract 5 from both sides.
2x=10
Subtract 5 from 15 to get 10.
x=\frac{10}{2}
Divide both sides by 2.
x=5
Divide 10 by 2 to get 5.
3\times 5+10=y+5
Consider the first equation. Insert the known values of variables into the equation.
15+10=y+5
Multiply 3 and 5 to get 15.
25=y+5
Add 15 and 10 to get 25.
y+5=25
Swap sides so that all variable terms are on the left hand side.
y=25-5
Subtract 5 from both sides.
y=20
Subtract 5 from 25 to get 20.
x=5 y=20
The system is now solved.