\left\{ \begin{array} { l } { 3 a + 2 x = 17 } \\ { x - y = 4 } \end{array} \right.
Solve for x, y
x=\frac{17-3a}{2}
y=\frac{9-3a}{2}
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2x+3a=17,x-y=4
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
2x+3a=17
Pick one of the two equations which is more simple to solve for x by isolating x on the left hand side of the equal sign.
2x=17-3a
Subtract 3a from both sides of the equation.
x=\frac{17-3a}{2}
Divide both sides by 2.
\frac{17-3a}{2}-y=4
Substitute \frac{17-3a}{2} for x in the other equation, x-y=4.
-y=\frac{3a-9}{2}
Subtract \frac{17-3a}{2} from both sides of the equation.
y=\frac{9-3a}{2}
Divide both sides by -1.
x=\frac{17-3a}{2},y=\frac{9-3a}{2}
The system is now solved.
Examples
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Limits
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