\left\{ \begin{array} { l } { 3 a + 14 b = 4 \quad \operatorname { mad } ( 26 ) } \\ { 13 a + 19 b = 13 \quad \bmod ( 26 ) } \end{array} \right.
Solve for a, b, m, d
a\in \mathrm{C}\setminus 0,\frac{182}{125}\text{, }b=\frac{13\left(104adm-3\right)}{125}\text{, }m=-\frac{125a-182}{1976ad}\text{, }d\neq 0
a=\frac{182}{125}=1.456\text{, }b=-\frac{39}{125}=-0.312\text{, }m\neq 0\text{, }d=0
a=\frac{182}{125}=1.456\text{, }b=-\frac{39}{125}=-0.312\text{, }m=0
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