\left\{ \begin{array} { l } { 3 - 2 m = 5 } \\ { 2 + 2 y = 6 } \end{array} \right.
Solve for m, y
y=2
m=-1
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-2m=5-3
Consider the first equation. Subtract 3 from both sides.
-2m=2
Subtract 3 from 5 to get 2.
m=\frac{2}{-2}
Divide both sides by -2.
m=-1
Divide 2 by -2 to get -1.
2y=6-2
Consider the second equation. Subtract 2 from both sides.
2y=4
Subtract 2 from 6 to get 4.
y=\frac{4}{2}
Divide both sides by 2.
y=2
Divide 4 by 2 to get 2.
m=-1 y=2
The system is now solved.
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