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10\left(4+77-1\right)=x
Consider the second equation. Multiply 2 and 5 to get 10.
10\left(81-1\right)=x
Add 4 and 77 to get 81.
10\times 80=x
Subtract 1 from 81 to get 80.
800=x
Multiply 10 and 80 to get 800.
x=800
Swap sides so that all variable terms are on the left hand side.
3\left(y-3-1\right)=800
Consider the first equation. Insert the known values of variables into the equation.
y-3-1=\frac{800}{3}
Divide both sides by 3.
y-4=\frac{800}{3}
Subtract 1 from -3 to get -4.
y=\frac{800}{3}+4
Add 4 to both sides.
y=\frac{812}{3}
Add \frac{800}{3} and 4 to get \frac{812}{3}.
y=\frac{812}{3} x=800
The system is now solved.