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3x-30=2x-10
Consider the first equation. Use the distributive property to multiply 3 by x-10.
3x-30-2x=-10
Subtract 2x from both sides.
x-30=-10
Combine 3x and -2x to get x.
x=-10+30
Add 30 to both sides.
x=20
Add -10 and 30 to get 20.
3\left(y-10\right)=2y-10\times \frac{20}{2}
Consider the second equation. Insert the known values of variables into the equation.
3y-30=2y-10\times \frac{20}{2}
Use the distributive property to multiply 3 by y-10.
3y-30=2y-10\times 10
Divide 20 by 2 to get 10.
3y-30=2y-100
Multiply 10 and 10 to get 100.
3y-30-2y=-100
Subtract 2y from both sides.
y-30=-100
Combine 3y and -2y to get y.
y=-100+30
Add 30 to both sides.
y=-70
Add -100 and 30 to get -70.
x=20 y=-70
The system is now solved.