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12-3y+2=y-6
Consider the first equation. Use the distributive property to multiply 3 by 4-y.
14-3y=y-6
Add 12 and 2 to get 14.
14-3y-y=-6
Subtract y from both sides.
14-4y=-6
Combine -3y and -y to get -4y.
-4y=-6-14
Subtract 14 from both sides.
-4y=-20
Subtract 14 from -6 to get -20.
y=\frac{-20}{-4}
Divide both sides by -4.
y=5
Divide -20 by -4 to get 5.
2\left(x-5\right)+5x-4=0
Consider the second equation. Insert the known values of variables into the equation.
2x-10+5x-4=0
Use the distributive property to multiply 2 by x-5.
7x-10-4=0
Combine 2x and 5x to get 7x.
7x-14=0
Subtract 4 from -10 to get -14.
7x=14
Add 14 to both sides. Anything plus zero gives itself.
x=\frac{14}{7}
Divide both sides by 7.
x=2
Divide 14 by 7 to get 2.
y=5 x=2
The system is now solved.