\left\{ \begin{array} { l } { 3 \Delta = x } \\ { x + 1 = y } \end{array} \right.
Solve for x, y
x=3\Delta
y=3\Delta +1
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x=3\Delta
Consider the first equation. Swap sides so that all variable terms are on the left hand side.
3\Delta -y=-1
Substitute 3\Delta for x in the other equation, x-y=-1.
-y=-3\Delta -1
Subtract 3\Delta from both sides of the equation.
y=3\Delta +1
Divide both sides by -1.
x=3\Delta ,y=3\Delta +1
The system is now solved.
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