\left\{ \begin{array} { l } { 2 y - 4 = 0 } \\ { 3 x - y = 1 } \end{array} \right.
Solve for y, x
x=1
y=2
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2y=4
Consider the first equation. Add 4 to both sides. Anything plus zero gives itself.
y=\frac{4}{2}
Divide both sides by 2.
y=2
Divide 4 by 2 to get 2.
3x-2=1
Consider the second equation. Insert the known values of variables into the equation.
3x=1+2
Add 2 to both sides.
3x=3
Add 1 and 2 to get 3.
x=\frac{3}{3}
Divide both sides by 3.
x=1
Divide 3 by 3 to get 1.
y=2 x=1
The system is now solved.
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