Solve {l}{2y=16}{2y-z=10}

$$\left\{ \begin{array} { l } { 2 y = 16 } \\ { 2 y - z = 10 } \end{array} \right.$$

Solve for y, z

$$y=8$$

$$z=6$$

Solution Steps

Consider the first equation. Divide both sides by 2.

$$y=\frac{16}{2}$$

Divide 16 by 2 to get 8.

$$y=8$$

Consider the second equation. Insert the known values of variables into the equation.

$$2\times 8-z=10$$

Multiply 2 and 8 to get 16.

$$16-z=10$$

Subtract 16 from both sides.

$$-z=10-16$$

Subtract 16 from 10 to get -6.

$$-z=-6$$

Divide both sides by -1.

$$z=\frac{-6}{-1}$$

Fraction \frac{-6}{-1} can be simplified to 6 by removing the negative sign from both the numerator and the denominator.

$$z=6$$

The system is now solved.

$$y=8 z=6$$