\left\{ \begin{array} { l } { 2 y = 0 } \\ { 6 x + 3 y = 600 } \end{array} \right.
Solve for y, x
x=100
y=0
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y=0
Consider the first equation. Divide both sides by 2. Zero divided by any non-zero number gives zero.
6x+3\times 0=600
Consider the second equation. Insert the known values of variables into the equation.
6x+0=600
Multiply 3 and 0 to get 0.
6x=600
Anything plus zero gives itself.
x=\frac{600}{6}
Divide both sides by 6.
x=100
Divide 600 by 6 to get 100.
y=0 x=100
The system is now solved.
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