Solve {l}{2x-2y+8=0}{2x+6=0}

$$\left\{ \begin{array} { l } { 2 x - 2 y + 8 = 0 } \\ { 2 x + 6 = 0 } \end{array} \right.$$

Solve for x, y

$$x=-3$$

$$y=1$$

Solution Steps

Consider the second equation. Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$2x=-6$$

Divide both sides by 2.

$$x=\frac{-6}{2}$$

Divide -6 by 2 to get -3.

$$x=-3$$

Consider the first equation. Insert the known values of variables into the equation.

$$2\left(-3\right)-2y+8=0$$

Multiply 2 and -3 to get -6.

$$-6-2y+8=0$$

Add -6 and 8 to get 2.

$$2-2y=0$$

Subtract 2 from both sides. Anything subtracted from zero gives its negation.

$$-2y=-2$$

Divide both sides by -2.

$$y=\frac{-2}{-2}$$

Divide -2 by -2 to get 1.

$$y=1$$

The system is now solved.

$$x=-3 y=1$$