\left\{ \begin{array} { l } { 2 x + 8 y + 6 z = 20 } \\ { 4 x + 2 - 2 z = - 2 y } \\ { 3 x - y + z = 11 } \end{array} \right.
Solve for x, y, z
x=2
y=-1
z=4
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3x-y+z=11 4x+2-2z=-2y 2x+8y+6z=20
Reorder the equations.
y=3x+z-11
Solve 3x-y+z=11 for y.
4x+2-2z=-2\left(3x+z-11\right) 2x+8\left(3x+z-11\right)+6z=20
Substitute 3x+z-11 for y in the second and third equation.
x=2 z=\frac{54}{7}-\frac{13}{7}x
Solve these equations for x and z respectively.
z=\frac{54}{7}-\frac{13}{7}\times 2
Substitute 2 for x in the equation z=\frac{54}{7}-\frac{13}{7}x.
z=4
Calculate z from z=\frac{54}{7}-\frac{13}{7}\times 2.
y=3\times 2+4-11
Substitute 2 for x and 4 for z in the equation y=3x+z-11.
y=-1
Calculate y from y=3\times 2+4-11.
x=2 y=-1 z=4
The system is now solved.
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