Solve {l}{2x+4=0}{4y+x=6}

$$\left\{ \begin{array} { l } { 2 x + 4 = 0 } \\ { 4 y + x = 6 } \end{array} \right.$$

Solve for x, y

$$x=-2$$

$$y=2$$

Solution Steps

Consider the first equation. Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$2x=-4$$

Divide both sides by 2.

$$x=\frac{-4}{2}$$

Divide -4 by 2 to get -2.

$$x=-2$$

Consider the second equation. Insert the known values of variables into the equation.

$$4y-2=6$$

Add 2 to both sides.

$$4y=6+2$$

Add 6 and 2 to get 8.

$$4y=8$$

Divide both sides by 4.

$$y=\frac{8}{4}$$

Divide 8 by 4 to get 2.

$$y=2$$

The system is now solved.

$$x=-2 y=2$$