\left\{ \begin{array} { l } { 2 x + 3 y = 4 } \\ { y = 2 } \end{array} \right.
Solve for x, y
x=-1
y=2
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2x+3\times 2=4
Consider the first equation. Insert the known values of variables into the equation.
2x+6=4
Multiply 3 and 2 to get 6.
2x=4-6
Subtract 6 from both sides.
2x=-2
Subtract 6 from 4 to get -2.
x=\frac{-2}{2}
Divide both sides by 2.
x=-1
Divide -2 by 2 to get -1.
x=-1 y=2
The system is now solved.
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