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Solve for x, B
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2x+1=6
Consider the first equation. Divide 3 by 3 to get 1.
2x=6-1
Subtract 1 from both sides.
2x=5
Subtract 1 from 6 to get 5.
x=\frac{5}{2}
Divide both sides by 2.
2B-3\times \frac{5}{2}=-2
Consider the second equation. Insert the known values of variables into the equation.
2B-\frac{15}{2}=-2
Multiply -3 and \frac{5}{2} to get -\frac{15}{2}.
2B=-2+\frac{15}{2}
Add \frac{15}{2} to both sides.
2B=\frac{11}{2}
Add -2 and \frac{15}{2} to get \frac{11}{2}.
B=\frac{\frac{11}{2}}{2}
Divide both sides by 2.
B=\frac{11}{2\times 2}
Express \frac{\frac{11}{2}}{2} as a single fraction.
B=\frac{11}{4}
Multiply 2 and 2 to get 4.
x=\frac{5}{2} B=\frac{11}{4}
The system is now solved.