\left\{ \begin{array} { l } { 2 x + 1 = 0 } \\ { 3 y = 0 } \end{array} \right.
Solve for x, y
x=-\frac{1}{2}=-0.5
y=0
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2x=-1
Consider the first equation. Subtract 1 from both sides. Anything subtracted from zero gives its negation.
x=-\frac{1}{2}
Divide both sides by 2.
y=0
Consider the second equation. Divide both sides by 3. Zero divided by any non-zero number gives zero.
x=-\frac{1}{2} y=0
The system is now solved.
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