Solve {l}{18y-6=0}{4x-3y-2=0}

$$\left\{ \begin{array} { l } { 18 y - 6 = 0 } \\ { 4 x - 3 y - 2 = 0 } \end{array} \right.$$

Solve for y, x

$$x=\frac{3}{4}=0.75$$

$$y=\frac{1}{3}\approx 0.333333333$$

Solution Steps

Consider the first equation. Add 6 to both sides. Anything plus zero gives itself.

$$18y=6$$

Divide both sides by 18.

$$y=\frac{6}{18}$$

Reduce the fraction \frac{6}{18} to lowest terms by extracting and canceling out 6.

$$y=\frac{1}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$4x-3\times \frac{1}{3}-2=0$$

Multiply -3 and \frac{1}{3} to get -1.

$$4x-1-2=0$$

Subtract 2 from -1 to get -3.

$$4x-3=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$4x=3$$

Divide both sides by 4.

$$x=\frac{3}{4}$$

The system is now solved.

$$y=\frac{1}{3} x=\frac{3}{4}$$