Solve {l}{150k+b=35}{200k+6=10}

$$\left\{ \begin{array} { l } { 150 k + b = 35 } \\ { 200 k + 6 = 10 } \end{array} \right.$$

Solve for k, b

$$k=\frac{1}{50}=0.02$$

$$b=32$$

Solution Steps

Consider the second equation. Subtract 6 from both sides.

$$200k=10-6$$

Subtract 6 from 10 to get 4.

$$200k=4$$

Divide both sides by 200.

$$k=\frac{4}{200}$$

Reduce the fraction \frac{4}{200} to lowest terms by extracting and canceling out 4.

$$k=\frac{1}{50}$$

Consider the first equation. Insert the known values of variables into the equation.

$$150\times \frac{1}{50}+b=35$$

Multiply 150 and \frac{1}{50} to get 3.

$$3+b=35$$

Subtract 3 from both sides.

$$b=35-3$$

Subtract 3 from 35 to get 32.

$$b=32$$

The system is now solved.

$$k=\frac{1}{50} b=32$$