Solve {l}{15x+y=0}{16y=-3}

$$\left\{ \begin{array} { l } { 15 x + y = 0 } \\ { 16 y = - 3 } \end{array} \right.$$

Solve for x, y

$$x=\frac{1}{80}=0.0125$$

$$y=-\frac{3}{16}=-0.1875$$

Solution Steps

Consider the second equation. Divide both sides by 16.

$$y=-\frac{3}{16}$$

Consider the first equation. Insert the known values of variables into the equation.

$$15x-\frac{3}{16}=0$$

Add \frac{3}{16} to both sides. Anything plus zero gives itself.

$$15x=\frac{3}{16}$$

Divide both sides by 15.

$$x=\frac{\frac{3}{16}}{15}$$

Express \frac{\frac{3}{16}}{15} as a single fraction.

$$x=\frac{3}{16\times 15}$$

Multiply 16 and 15 to get 240.

$$x=\frac{3}{240}$$

Reduce the fraction \frac{3}{240} to lowest terms by extracting and canceling out 3.

$$x=\frac{1}{80}$$

The system is now solved.

$$x=\frac{1}{80} y=-\frac{3}{16}$$