Solve {l}{12x-4y=-52}{-3x+8=83}

$$\left\{ \begin{array} { l } { 12 x - 4 y = - 52 } \\ { - 3 x + 8 = 83 } \end{array} \right.$$

Solve for x, y

$$x=-25$$

$$y=-62$$

Solution Steps

Consider the second equation. Subtract 8 from both sides.

$$-3x=83-8$$

Subtract 8 from 83 to get 75.

$$-3x=75$$

Divide both sides by -3.

$$x=\frac{75}{-3}$$

Divide 75 by -3 to get -25.

$$x=-25$$

Consider the first equation. Insert the known values of variables into the equation.

$$12\left(-25\right)-4y=-52$$

Multiply 12 and -25 to get -300.

$$-300-4y=-52$$

Add 300 to both sides.

$$-4y=-52+300$$

Add -52 and 300 to get 248.

$$-4y=248$$

Divide both sides by -4.

$$y=\frac{248}{-4}$$

Divide 248 by -4 to get -62.

$$y=-62$$

The system is now solved.

$$x=-25 y=-62$$