\left\{ \begin{array} { l } { 12 + 2 a = 18 } \\ { 3 b - 4 = 7 } \end{array} \right.
Solve for a, b
a=3
b = \frac{11}{3} = 3\frac{2}{3} \approx 3.666666667
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2a=18-12
Consider the first equation. Subtract 12 from both sides.
2a=6
Subtract 12 from 18 to get 6.
a=\frac{6}{2}
Divide both sides by 2.
a=3
Divide 6 by 2 to get 3.
3b=7+4
Consider the second equation. Add 4 to both sides.
3b=11
Add 7 and 4 to get 11.
b=\frac{11}{3}
Divide both sides by 3.
a=3 b=\frac{11}{3}
The system is now solved.
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