Solve {l}{11.9*10^-2*7*(x-0.48)^2/0.45=141.47/2[2(1.2-0.46)(1.2-y)-(1.2-y)^2]}{x=0.48+51.6/102(y-0.46)}

$$\left\{ \begin{array} { l } { 11.9 \times 10 ^ { - 2 } \times 7 \times \frac { ( x - 0.48 ) ^ { 2 } } { 0.45 } = \frac { 141.47 } { 2 } [ 2 ( 1.2 - 0.46 ) ( 1.2 - y ) - ( 1.2 - y ) ^ { 2 } ] } \\ { x = 0.48 + \frac { 51.6 } { 102 } ( y - 0.46 ) } \end{array} \right.$$

Solve for x, y

$$x=-\frac{4773\sqrt{144602221}}{153832150}+0.48\approx 0.106894367\text{, }y=-\frac{111\sqrt{144602221}}{1809790}+0.46\approx -0.277534391$$

$$x=\frac{4773\sqrt{144602221}}{153832150}+0.48\approx 0.853105633\text{, }y=\frac{111\sqrt{144602221}}{1809790}+0.46\approx 1.197534391$$