Solve {l}{10d+25=81.8}{d+q=14}

$$\left\{ \begin{array} { l } { 10 d + 25 = 81.8 } \\ { d + q = 14 } \end{array} \right.$$

Solve for d, q

$$d=5.68$$

$$q=8.32$$

Solution Steps

Consider the first equation. Subtract 25 from both sides.

$$10d=81.8-25$$

Subtract 25 from 81.8 to get 56.8.

$$10d=56.8$$

Divide both sides by 10.

$$d=\frac{56.8}{10}$$

Expand \frac{56.8}{10} by multiplying both numerator and the denominator by 10.

$$d=\frac{568}{100}$$

Reduce the fraction \frac{568}{100} to lowest terms by extracting and canceling out 4.

$$d=\frac{142}{25}$$

Consider the second equation. Insert the known values of variables into the equation.

$$\frac{142}{25}+q=14$$

Subtract \frac{142}{25} from both sides.

$$q=14-\frac{142}{25}$$

Subtract \frac{142}{25} from 14 to get \frac{208}{25}.

$$q=\frac{208}{25}$$

The system is now solved.

$$d=\frac{142}{25} q=\frac{208}{25}$$