Solve {l}{1.5*20*+1.5*10y=1000}{1.2*110x+1.2*120y=97200}

$$\left\{ \begin{array} { l } { 1.5 \times 20 \times + 1.5 \times 10 y = 1000 } \\ { 1.2 \times 110 x + 1.2 \times 120 y = 97200 } \end{array} \right.$$

Solve for y, x

$$x = \frac{24220}{33} = 733\frac{31}{33} \approx 733.939393939$$

$$y = \frac{20}{9} = 2\frac{2}{9} \approx 2.222222222$$

Steps Using Substitution

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$$450y=1000,144y+132x=97200$$

Pick one of the two equations which is more simple to solve for y by isolating y on the left hand side of the equal sign.

$$450y=1000$$

Divide both sides by 450.

$$y=\frac{20}{9}$$

Substitute \frac{20}{9} for y in the other equation, 144y+132x=97200.

$$144\times \frac{20}{9}+132x=97200$$

Multiply 144 times \frac{20}{9}.

$$320+132x=97200$$

Subtract 320 from both sides of the equation.

$$132x=96880$$

Divide both sides by 132.

$$x=\frac{24220}{33}$$

The system is now solved.

$$y=\frac{20}{9},x=\frac{24220}{33}$$