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Solve for x, y
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0-2y=4
Consider the first equation. Anything times zero gives zero.
-2y=4
Anything plus zero gives itself.
y=\frac{4}{-2}
Divide both sides by -2.
y=-2
Divide 4 by -2 to get -2.
-2=5x+3
Consider the second equation. Insert the known values of variables into the equation.
5x+3=-2
Swap sides so that all variable terms are on the left hand side.
5x=-2-3
Subtract 3 from both sides.
5x=-5
Subtract 3 from -2 to get -5.
x=\frac{-5}{5}
Divide both sides by 5.
x=-1
Divide -5 by 5 to get -1.
x=-1 y=-2
The system is now solved.