\left\{ \begin{array} { l } { 0 x + 3 y = 3 } \\ { 5 x - 3 y = 9 } \end{array} \right.
Solve for x, y
x = \frac{12}{5} = 2\frac{2}{5} = 2.4
y=1
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0+3y=3
Consider the first equation. Anything times zero gives zero.
3y=3
Anything plus zero gives itself.
y=\frac{3}{3}
Divide both sides by 3.
y=1
Divide 3 by 3 to get 1.
5x-3=9
Consider the second equation. Insert the known values of variables into the equation.
5x=9+3
Add 3 to both sides.
5x=12
Add 9 and 3 to get 12.
x=\frac{12}{5}
Divide both sides by 5.
x=\frac{12}{5} y=1
The system is now solved.
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Limits
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