\left\{ \begin{array} { l } { 0 = a - b + c } \\ { 3 = c } \\ { 0 = 9 a + 3 b + c } \end{array} \right.
Solve for a, b, c
a=-1
b=2
c=3
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3=c 0=a-b+c 0=9a+3b+c
Reorder the equations.
c=3
Solve 3=c for c.
0=a-b+3 0=9a+3b+3
Substitute 3 for c in the second and third equation.
b=a+3 a=-\frac{1}{3}-\frac{1}{3}b
Solve these equations for b and a respectively.
a=-\frac{1}{3}-\frac{1}{3}\left(a+3\right)
Substitute a+3 for b in the equation a=-\frac{1}{3}-\frac{1}{3}b.
a=-1
Solve a=-\frac{1}{3}-\frac{1}{3}\left(a+3\right) for a.
b=-1+3
Substitute -1 for a in the equation b=a+3.
b=2
Calculate b from b=-1+3.
a=-1 b=2 c=3
The system is now solved.
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