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Solve for a, b, c
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3=c 0=9a-3b+c 0=a+b+c
Reorder the equations.
c=3
Solve 3=c for c.
0=9a-3b+3 0=a+b+3
Substitute 3 for c in the second and third equation.
b=1+3a a=-b-3
Solve these equations for b and a respectively.
a=-\left(1+3a\right)-3
Substitute 1+3a for b in the equation a=-b-3.
a=-1
Solve a=-\left(1+3a\right)-3 for a.
b=1+3\left(-1\right)
Substitute -1 for a in the equation b=1+3a.
b=-2
Calculate b from b=1+3\left(-1\right).
a=-1 b=-2 c=3
The system is now solved.