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Solve for t, s, z
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3t+5=0
Consider the second equation. Swap sides so that all variable terms are on the left hand side.
3t=-5
Subtract 5 from both sides. Anything subtracted from zero gives its negation.
t=-\frac{5}{3}
Divide both sides by 3.
0=4-4\left(-\frac{5}{3}\right)+3s
Consider the first equation. Insert the known values of variables into the equation.
0=4+\frac{20}{3}+3s
Multiply -4 and -\frac{5}{3} to get \frac{20}{3}.
0=\frac{32}{3}+3s
Add 4 and \frac{20}{3} to get \frac{32}{3}.
\frac{32}{3}+3s=0
Swap sides so that all variable terms are on the left hand side.
3s=-\frac{32}{3}
Subtract \frac{32}{3} from both sides. Anything subtracted from zero gives its negation.
s=\frac{-\frac{32}{3}}{3}
Divide both sides by 3.
s=\frac{-32}{3\times 3}
Express \frac{-\frac{32}{3}}{3} as a single fraction.
s=\frac{-32}{9}
Multiply 3 and 3 to get 9.
s=-\frac{32}{9}
Fraction \frac{-32}{9} can be rewritten as -\frac{32}{9} by extracting the negative sign.
z=-2-\left(-\frac{5}{3}\right)-3\left(-\frac{32}{9}\right)
Consider the third equation. Insert the known values of variables into the equation.
z=-2+\frac{5}{3}-3\left(-\frac{32}{9}\right)
Multiply -1 and -\frac{5}{3} to get \frac{5}{3}.
z=-\frac{1}{3}-3\left(-\frac{32}{9}\right)
Add -2 and \frac{5}{3} to get -\frac{1}{3}.
z=-\frac{1}{3}+\frac{32}{3}
Multiply -3 and -\frac{32}{9} to get \frac{32}{3}.
z=\frac{31}{3}
Add -\frac{1}{3} and \frac{32}{3} to get \frac{31}{3}.
t=-\frac{5}{3} s=-\frac{32}{9} z=\frac{31}{3}
The system is now solved.