Solve {l}{-4-6s=20-4}{32+6=8+2t}

$$\left\{ \begin{array} { l } { - 4 - 6 s = 20 - 4 } \\ { 32 + 6 = 8 + 2 t } \end{array} \right.$$

Solve for s, t

$$t=15$$

$$s = -\frac{10}{3} = -3\frac{1}{3} \approx -3.333333333$$

Solution Steps

Consider the first equation. Subtract 4 from 20 to get 16.

$$-4-6s=16$$

Add 4 to both sides.

$$-6s=16+4$$

Add 16 and 4 to get 20.

$$-6s=20$$

Divide both sides by -6.

$$s=\frac{20}{-6}$$

Reduce the fraction \frac{20}{-6} to lowest terms by extracting and canceling out 2.

$$s=-\frac{10}{3}$$

Consider the second equation. Add 32 and 6 to get 38.

$$38=8+2t$$

Swap sides so that all variable terms are on the left hand side.

$$8+2t=38$$

Subtract 8 from both sides.

$$2t=38-8$$

Subtract 8 from 38 to get 30.

$$2t=30$$

Divide both sides by 2.

$$t=\frac{30}{2}$$

Divide 30 by 2 to get 15.

$$t=15$$

The system is now solved.

$$s=-\frac{10}{3} t=15$$