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Solve for k, b
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5k=-6
Consider the second equation. Subtract 6 from both sides. Anything subtracted from zero gives its negation.
k=-\frac{6}{5}
Divide both sides by 5.
-3\left(-\frac{6}{5}\right)+b=-4
Consider the first equation. Insert the known values of variables into the equation.
\frac{18}{5}+b=-4
Multiply -3 and -\frac{6}{5} to get \frac{18}{5}.
b=-4-\frac{18}{5}
Subtract \frac{18}{5} from both sides.
b=-\frac{38}{5}
Subtract \frac{18}{5} from -4 to get -\frac{38}{5}.
k=-\frac{6}{5} b=-\frac{38}{5}
The system is now solved.