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Solve for b, k
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-\frac{4+3}{4}=b
Consider the first equation. Multiply 1 and 4 to get 4.
-\frac{7}{4}=b
Add 4 and 3 to get 7.
b=-\frac{7}{4}
Swap sides so that all variable terms are on the left hand side.
-2=\frac{1}{2}k-\frac{7}{4}
Consider the second equation. Insert the known values of variables into the equation.
\frac{1}{2}k-\frac{7}{4}=-2
Swap sides so that all variable terms are on the left hand side.
\frac{1}{2}k=-2+\frac{7}{4}
Add \frac{7}{4} to both sides.
\frac{1}{2}k=-\frac{1}{4}
Add -2 and \frac{7}{4} to get -\frac{1}{4}.
k=-\frac{1}{4}\times 2
Multiply both sides by 2, the reciprocal of \frac{1}{2}.
k=-\frac{1}{2}
Multiply -\frac{1}{4} and 2 to get -\frac{1}{2}.
b=-\frac{7}{4} k=-\frac{1}{2}
The system is now solved.