\left\{ \begin{array} { l } { \frac { x - 12 } { - 38 } = \frac { y - 131 } { 19 } = \frac { z + 1 } { 38 } } \\ { x = 1 } \end{array} \right.
Evaluate (complex solution)
-\frac{x}{38}+\frac{6}{19}=\frac{y-131}{19}\text{ and }\frac{y-131}{19}=\frac{z+1}{38},\ x=1
Solve for x
x=1
y=\frac{273}{2}\text{ and }z=10
Solve for z
z=10
y=\frac{273}{2}\text{ and }x=1
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