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2x+3\times 4=-6
Consider the first equation. Multiply both sides of the equation by 6, the least common multiple of 3,2.
2x+12=-6
Multiply 3 and 4 to get 12.
2x=-6-12
Subtract 12 from both sides.
2x=-18
Subtract 12 from -6 to get -18.
x=\frac{-18}{2}
Divide both sides by 2.
x=-9
Divide -18 by 2 to get -9.
2\left(-9\right)-y=4
Consider the second equation. Insert the known values of variables into the equation.
-18-y=4
Multiply 2 and -9 to get -18.
-y=4+18
Add 18 to both sides.
-y=22
Add 4 and 18 to get 22.
y=-22
Divide both sides by -1.
x=-9 y=-22
The system is now solved.