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3x-2\left(x-2\right)=12
Consider the first equation. Multiply both sides of the equation by 6, the least common multiple of 2,3.
3x-2x+4=12
Use the distributive property to multiply -2 by x-2.
x+4=12
Combine 3x and -2x to get x.
x=12-4
Subtract 4 from both sides.
x=8
Subtract 4 from 12 to get 8.
3\times 8+2y=16
Consider the second equation. Insert the known values of variables into the equation.
24+2y=16
Multiply 3 and 8 to get 24.
2y=16-24
Subtract 24 from both sides.
2y=-8
Subtract 24 from 16 to get -8.
y=\frac{-8}{2}
Divide both sides by 2.
y=-4
Divide -8 by 2 to get -4.
x=8 y=-4
The system is now solved.