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3x=2\left(-1\right)
Consider the first equation. Multiply both sides of the equation by 6, the least common multiple of 2,3.
3x=-2
Multiply 2 and -1 to get -2.
x=-\frac{2}{3}
Divide both sides by 3.
-\frac{2}{3}+\frac{1}{4}=y+\frac{1}{4}
Consider the second equation. Insert the known values of variables into the equation.
-\frac{5}{12}=y+\frac{1}{4}
Add -\frac{2}{3} and \frac{1}{4} to get -\frac{5}{12}.
y+\frac{1}{4}=-\frac{5}{12}
Swap sides so that all variable terms are on the left hand side.
y=-\frac{5}{12}-\frac{1}{4}
Subtract \frac{1}{4} from both sides.
y=-\frac{2}{3}
Subtract \frac{1}{4} from -\frac{5}{12} to get -\frac{2}{3}.
x=-\frac{2}{3} y=-\frac{2}{3}
The system is now solved.