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8x-6x=-18x+49
Consider the second equation. Multiply both sides of the equation by 3.
2x=-18x+49
Combine 8x and -6x to get 2x.
2x+18x=49
Add 18x to both sides.
20x=49
Combine 2x and 18x to get 20x.
x=\frac{49}{20}
Divide both sides by 20.
\frac{\frac{49}{20}+4y}{5}+\frac{2}{15}\left(y+1\right)=\frac{2\left(3+\frac{49}{20}\right)}{10}
Consider the first equation. Insert the known values of variables into the equation.
6\left(\frac{49}{20}+4y\right)+4\left(y+1\right)=3\times 2\left(3+\frac{49}{20}\right)
Multiply both sides of the equation by 30, the least common multiple of 5,15,10.
\frac{147}{10}+24y+4\left(y+1\right)=3\times 2\left(3+\frac{49}{20}\right)
Use the distributive property to multiply 6 by \frac{49}{20}+4y.
\frac{147}{10}+24y+4y+4=3\times 2\left(3+\frac{49}{20}\right)
Use the distributive property to multiply 4 by y+1.
\frac{147}{10}+28y+4=3\times 2\left(3+\frac{49}{20}\right)
Combine 24y and 4y to get 28y.
\frac{187}{10}+28y=3\times 2\left(3+\frac{49}{20}\right)
Add \frac{147}{10} and 4 to get \frac{187}{10}.
\frac{187}{10}+28y=6\left(3+\frac{49}{20}\right)
Multiply 3 and 2 to get 6.
\frac{187}{10}+28y=6\times \frac{109}{20}
Add 3 and \frac{49}{20} to get \frac{109}{20}.
\frac{187}{10}+28y=\frac{327}{10}
Multiply 6 and \frac{109}{20} to get \frac{327}{10}.
28y=\frac{327}{10}-\frac{187}{10}
Subtract \frac{187}{10} from both sides.
28y=14
Subtract \frac{187}{10} from \frac{327}{10} to get 14.
y=\frac{14}{28}
Divide both sides by 28.
y=\frac{1}{2}
Reduce the fraction \frac{14}{28} to lowest terms by extracting and canceling out 14.
x=\frac{49}{20} y=\frac{1}{2}
The system is now solved.