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25+2x=-40
Consider the first equation. Multiply both sides of the equation by 10, the least common multiple of 2,5.
2x=-40-25
Subtract 25 from both sides.
2x=-65
Subtract 25 from -40 to get -65.
x=-\frac{65}{2}
Divide both sides by 2.
\frac{y}{3}+\frac{-\frac{65}{2}}{6}=\frac{1}{6}
Consider the second equation. Insert the known values of variables into the equation.
2y-\frac{65}{2}=1
Multiply both sides of the equation by 6, the least common multiple of 3,6.
2y=1+\frac{65}{2}
Add \frac{65}{2} to both sides.
2y=\frac{67}{2}
Add 1 and \frac{65}{2} to get \frac{67}{2}.
y=\frac{\frac{67}{2}}{2}
Divide both sides by 2.
y=\frac{67}{2\times 2}
Express \frac{\frac{67}{2}}{2} as a single fraction.
y=\frac{67}{4}
Multiply 2 and 2 to get 4.
x=-\frac{65}{2} y=\frac{67}{4}
The system is now solved.