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9+5y=105
Consider the first equation. Multiply both sides of the equation by 15, the least common multiple of 5,3.
5y=105-9
Subtract 9 from both sides.
5y=96
Subtract 9 from 105 to get 96.
y=\frac{96}{5}
Divide both sides by 5.
\frac{\frac{96}{5}}{5}-\frac{x}{2}=-2
Consider the second equation. Insert the known values of variables into the equation.
2\times \frac{96}{5}-5x=-20
Multiply both sides of the equation by 10, the least common multiple of 5,2.
\frac{192}{5}-5x=-20
Multiply 2 and \frac{96}{5} to get \frac{192}{5}.
-5x=-20-\frac{192}{5}
Subtract \frac{192}{5} from both sides.
-5x=-\frac{292}{5}
Subtract \frac{192}{5} from -20 to get -\frac{292}{5}.
x=\frac{-\frac{292}{5}}{-5}
Divide both sides by -5.
x=\frac{-292}{5\left(-5\right)}
Express \frac{-\frac{292}{5}}{-5} as a single fraction.
x=\frac{-292}{-25}
Multiply 5 and -5 to get -25.
x=\frac{292}{25}
Fraction \frac{-292}{-25} can be simplified to \frac{292}{25} by removing the negative sign from both the numerator and the denominator.
y=\frac{96}{5} x=\frac{292}{25}
The system is now solved.