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x=2790\times \frac{10}{3}
Consider the first equation. Multiply both sides by \frac{10}{3}, the reciprocal of \frac{3}{10}.
x=9300
Multiply 2790 and \frac{10}{3} to get 9300.
y=\frac{7}{10}\times 9300
Consider the second equation. Insert the known values of variables into the equation.
y=6510
Multiply \frac{7}{10} and 9300 to get 6510.
x=9300 y=6510
The system is now solved.