Solve {l}{1/3+6/6=14}{3/4-6/4=-30}

$$\left\{ \begin{array} { l } { \frac { 1 } { 3 } + \frac { 6 } { 6 } = 14 } \\ { \frac { 3 } { 4 } - \frac { 6 } { 4 } = - 30 } \end{array} \right.$$

Verify

Solution Steps

Divide 6 by 6 to get 1.

$$\frac{1}{3}+1=14\text{ and }\frac{3}{4}-\frac{6}{4}=-30$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{1}{3}+\frac{3}{3}=14\text{ and }\frac{3}{4}-\frac{6}{4}=-30$$

Since \frac{1}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{1+3}{3}=14\text{ and }\frac{3}{4}-\frac{6}{4}=-30$$

Add 1 and 3 to get 4.

$$\frac{4}{3}=14\text{ and }\frac{3}{4}-\frac{6}{4}=-30$$

Convert 14 to fraction \frac{42}{3}.

$$\frac{4}{3}=\frac{42}{3}\text{ and }\frac{3}{4}-\frac{6}{4}=-30$$

Compare \frac{4}{3} and \frac{42}{3}.

$$\text{false}\text{ and }\frac{3}{4}-\frac{6}{4}=-30$$

Since \frac{3}{4} and \frac{6}{4} have the same denominator, subtract them by subtracting their numerators.

$$\text{false}\text{ and }\frac{3-6}{4}=-30$$

Subtract 6 from 3 to get -3.

$$\text{false}\text{ and }-\frac{3}{4}=-30$$

Convert -30 to fraction -\frac{120}{4}.

$$\text{false}\text{ and }-\frac{3}{4}=-\frac{120}{4}$$

Compare -\frac{3}{4} and -\frac{120}{4}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$