\left\{ \begin{array} { l } { \frac { 1 } { 2 } k + b = - \frac { 1 } { a } } \\ { 2 k + b = 2 } \end{array} \right.
Solve for k, b, a
k=\frac{4}{3}+\frac{2}{3a}
b=-\frac{2}{3}-\frac{4}{3a}
a\neq 0
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