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\frac{1}{3}\times 5+2y=11
Consider the second equation. Insert the known values of variables into the equation.
\frac{5}{3}+2y=11
Multiply \frac{1}{3} and 5 to get \frac{5}{3}.
2y=11-\frac{5}{3}
Subtract \frac{5}{3} from both sides.
2y=\frac{28}{3}
Subtract \frac{5}{3} from 11 to get \frac{28}{3}.
y=\frac{\frac{28}{3}}{2}
Divide both sides by 2.
y=\frac{28}{3\times 2}
Express \frac{\frac{28}{3}}{2} as a single fraction.
y=\frac{28}{6}
Multiply 3 and 2 to get 6.
y=\frac{14}{3}
Reduce the fraction \frac{28}{6} to lowest terms by extracting and canceling out 2.
x=5 y=\frac{14}{3}
The system is now solved.