\left\{ \begin{array} { c } { x = 5 } \\ { \frac { 1 } { 3 } x + 2 y = 11 } \end{array} \right.
Solve for x, y
x=5
y = \frac{14}{3} = 4\frac{2}{3} \approx 4.666666667
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\frac{1}{3}\times 5+2y=11
Consider the second equation. Insert the known values of variables into the equation.
\frac{5}{3}+2y=11
Multiply \frac{1}{3} and 5 to get \frac{5}{3}.
2y=11-\frac{5}{3}
Subtract \frac{5}{3} from both sides.
2y=\frac{28}{3}
Subtract \frac{5}{3} from 11 to get \frac{28}{3}.
y=\frac{\frac{28}{3}}{2}
Divide both sides by 2.
y=\frac{28}{3\times 2}
Express \frac{\frac{28}{3}}{2} as a single fraction.
y=\frac{28}{6}
Multiply 3 and 2 to get 6.
y=\frac{14}{3}
Reduce the fraction \frac{28}{6} to lowest terms by extracting and canceling out 2.
x=5 y=\frac{14}{3}
The system is now solved.
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